# Root and enclosure certificate for T627 Write x=xi>0, l=2k+2 and a(x)=atan(1/x). Let p_0=1, p_1=x, r_0=0, r_1=1. Both polynomial sequences obey (n+1) v_(n+1) = (2n+1) x v_n + n v_(n-1). For even l, set q_l=p_l a-r_l. All polynomial arithmetic uses QQ[x]. The generator verifies the polynomial identity (1+x^2)(r_l p_l' - r_l' p_l) - p_l^2 = -1. Consequently (q_l/p_l)'=-1/((1+x^2)p_l^2). The coefficients of p_l are nonnegative and its constant coefficient is positive. Since r_l has degree l-1, q_l/p_l tends to zero at infinity. Integration proves that q_l is exactly the real oblate function in the source's defining integral. This also fixes its branch. There is no appeal to a numerical fit of a special function. For p_2=(1+3x^2)/2 and q_2=p_2 a-3x/2, the right side of AKM (3) simplifies to 2x(1-xa). Thus the original equation is equivalent to H(x) = a(x) - B(x)/A(x) = 0, A=p_l^2+x^2, B=p_l r_l+x. Its derivative has the positive denominator (1+x^2)A^2 and numerator N=(1+x^2)(B A'-B' A)-A^2. For each l=4,6,...,22 the generator verifies exactly that N has a negative constant coefficient, only nonnegative other coefficients, and positive leading coefficient. Hence N is strictly increasing on x>0 and has exactly one positive zero. H first decreases, then increases. H(0+)=pi/2; deg B