History of Zeros of the $L$-functions of level one cusp forms

 Title: Zeros of the $L$-functions of level one cusp forms-Definition: For $f_{k,i}(q)=\sum_{m\geq1}a_mq^m$, the $i$th normalised Hecke eigenform-  in $S_k(\mathrm{SL}_2(\mathbb{Z}))$ CITE{WikiCusp} ordered by increasing embedded-  $a_2$, this table gives, in increasing order from $n=1$, the positive ordinates-  $t_n$ for zeros $L(f_{k,i},s)=0$ of its $L$-function CITE{WikiL} on the critical-  line $\operatorname{Re}s=k/2$.+Definition: For the normalised Hecke eigenforms $f_{k,i}\in S_k(\mathrm{SL}_2(\mathbb{Z}))$+  CITE{WikiCusp}, this table gives the positive ordinates $t_n$ of zeros of $L(f_{k,i},s)$+  CITE{WikiL} on $\operatorname{Re}s=k/2$, ordered increasingly from $n=1$. Parameters:   k:

     constraints: $n\geq1$ Comments:-  comment-normalisation: The table uses the arithmetic normalisation with $a_1=1$,-    where $L(f,s)$ is the analytic continuation of $\sum a_mm^{-s}$. In this normalisation-    the functional equation relates $s$ and $k-s$, the centre is $s=k/2$, and the-    nontrivial zeros lie in the central strip $(k-1)/2\leq\operatorname{Re}s\leq(k+1)/2$;+  comment-normalisation: 'The table uses the arithmetic normalisation: for $f(q)=\sum_{m\geq1}a_mq^m$,+    $a_1=1$ and $L(f,s)$ is the analytic continuation of $\sum_{m\geq1}a_m m^{-s}$.+    In this normalisation the functional equation relates $s$ and $k-s$, the centre+    is $s=k/2$, and the nontrivial zeros lie in the central strip $(k-1)/2\leq\operatorname{Re}s\leq(k+1)/2$;     the entries here are zeros on the critical line $\operatorname{Re}s=k/2$. The     analytic normalisation with centre $1/2$ is $L^{\mathrm{an}}(f,s)=L(f,s+(k-1)/2)$,     so the ordinates $t_n$ are the same in both normalisations. The $k=12$ rows are-    zeros of the Ramanujan tau $L$-function in this normalisation.+    zeros of the Ramanujan tau $L$-function in this normalisation.'   comment-ordering: The index $i$ counts the eigenforms of weight $k$ in increasing     order of the embedded $T_2$-eigenvalue $a_2$; this is not necessarily the order