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comment-component: The table stores one homogeneous component per row, not the total Segre class $1+s_1+s_2+\cdots$ truncated at degree $n$.- comment-zero: The constant component is $s_0=1$ and is stated in Formula CITE{formula-zero},- rather than stored as a row.+ comment-zero: The constant component is $s_0=1$ and is not stored as a row; the+ table begins at $n=1$. comment-rank: There is no rank parameter in the table. For a vector bundle of rank $r$, the universal polynomial is specialised by setting $c_j=0$ for $j>r$.
h_n(x_1,x_2,\dots)$, where $h_n$ is the HREF{Complete_homogeneous_symmetric_polynomials}[complete homogeneous symmetric polynomial].- formula-zero: $s_0=1$.- formula-first: $s_1=-c_1$, $s_2=c_1^2-c_2$, and $s_3=-c_1^3+2c_1c_2-c_3$. Programs: program-sage:
\ R = PolynomialRing(ZZ, [\"c%s\" % i for i in range(1, n + 1)])\n c = [R(1)]\ \ + list(R.gens())\n s = [R(1)]\n for m in range(1, n + 1):\n s.append(-sum(c[j]\- \ * s[m - j] for j in range(1, m + 1)))\n return s[n]\n\nprint(segre_component(6))"+ \ * s[m - j] for j in range(1, m + 1)))\n return s[n]\n\nprint(segre_component(7))" Similar tables: - table: HREF{Todd_polynomials}[Todd polynomials]
variables - table: HREF{Chern_character_polynomials}[Chern character polynomials]- relation: store another universal characteristic-class polynomial in the same Chern-class- variables+ relation: store the components of $\operatorname{ch}(E)=\sum_i e^{x_i}$ in the same+ Chern-class variables - table: HREF{Complete_homogeneous_symmetric_polynomials}[Complete homogeneous symmetric polynomials]- relation: give the $h_n$ whose signed Chern-root expressions are stored here+ relation: give the $h_n$ in the Chern roots; the entries here are $(-1)^n h_n$ rewritten+ in the Chern classes - table: HREF{Elementary_symmetric_polynomials}[Elementary symmetric polynomials] relation: give the elementary symmetric functions $e_j$ that are renamed as Chern
the Chern-root identity in Formula CITE{formula-roots} and by substituting the Chern classes of $T\mathbb P^m$ for $1\leq n\leq m\leq 6$, which gives $s_n(T\mathbb- P^m)=(-1)^n\binom{m+n}{n}h^n$.+ P^m)=(-1)^n\binom{m+n}{n}h^n$, where $h$ is the hyperplane class. Display properties: number-header: $s_n$ Numbers:-- params:- n: '1'- number: -c1-- params:- n: '2'- number: c1^2 - c2-- params:- n: '3'- number: -c1^3 + 2*c1*c2 - c3-- params:- n: '4'- number: c1^4 - 3*c1^2*c2 + c2^2 + 2*c1*c3 - c4-- params:- n: '5'- number: -c1^5 + 4*c1^3*c2 - 3*c1*c2^2 - 3*c1^2*c3 + 2*c2*c3 + 2*c1*c4 - c5-- params:- n: '6'- number: c1^6 - 5*c1^4*c2 + 6*c1^2*c2^2 + 4*c1^3*c3 - c2^3 - 6*c1*c2*c3 - 3*c1^2*c4+ '1': -c1+ '2': c1^2 - c2+ '3': -c1^3 + 2*c1*c2 - c3+ '4': c1^4 - 3*c1^2*c2 + c2^2 + 2*c1*c3 - c4+ '5': -c1^5 + 4*c1^3*c2 - 3*c1*c2^2 - 3*c1^2*c3 + 2*c2*c3 + 2*c1*c4 - c5+ '6': c1^6 - 5*c1^4*c2 + 6*c1^2*c2^2 + 4*c1^3*c3 - c2^3 - 6*c1*c2*c3 - 3*c1^2*c4 + c3^2 + 2*c2*c4 + 2*c1*c5 - c6
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