Known solutions of the Fermat-Catalan equation $x^p+y^q=z^r$
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Numbers
solution
$x$, $y$, $z$, or $z^r$
$2^5+7^2=3^4$
$x$:
2
$2^5+7^2=3^4$
$y$:
7
$2^5+7^2=3^4$
$z$:
3
$2^5+7^2=3^4$
$z^r$:
81
$13^2+7^3=2^9$
$x$:
13
$13^2+7^3=2^9$
$y$:
7
$13^2+7^3=2^9$
$z$:
2
$13^2+7^3=2^9$
$z^r$:
512
$2^7+17^3=71^2$
$x$:
2
$2^7+17^3=71^2$
$y$:
17
$2^7+17^3=71^2$
$z$:
71
$2^7+17^3=71^2$
$z^r$:
5041
$3^5+11^4=122^2$
$x$:
3
$3^5+11^4=122^2$
$y$:
11
$3^5+11^4=122^2$
$z$:
122
$3^5+11^4=122^2$
$z^r$:
14884
$33^8+1549034^2=15613^3$
$x$:
33
$33^8+1549034^2=15613^3$
$y$:
1549034
$33^8+1549034^2=15613^3$
$z$:
15613
$33^8+1549034^2=15613^3$
$z^r$:
3805914951397
$1414^3+2213459^2=65^7$
$x$:
1414
$1414^3+2213459^2=65^7$
$y$:
2213459
$1414^3+2213459^2=65^7$
$z$:
65
$1414^3+2213459^2=65^7$
$z^r$:
4902227890625
$9262^3+15312283^2=113^7$
$x$:
9262
$9262^3+15312283^2=113^7$
$y$:
15312283
$9262^3+15312283^2=113^7$
$z$:
113
$9262^3+15312283^2=113^7$
$z^r$:
235260548044817
$17^7+76271^3=21063928^2$
$x$:
17
$17^7+76271^3=21063928^2$
$y$:
76271
$17^7+76271^3=21063928^2$
$z$:
21063928
$17^7+76271^3=21063928^2$
$z^r$:
443689062789184
$43^8+96222^3=30042907^2$
$x$:
43
$43^8+96222^3=30042907^2$
$y$:
96222
$43^8+96222^3=30042907^2$
$z$:
30042907
$43^8+96222^3=30042907^2$
$z^r$:
902576261010649
Definition
Known coprime positive-integer solutions of the Fermat-Catalan equation $x^p+y^q=z^r$ [1], with $x,y,z>1$, $\frac1p+\frac1q+\frac1r<1$ and $x^p<y^q$. The stored integers $x$, $y$, $z$ and $z^r$ are parts of one solution.
Parameters
solution
—   sum (a perfect power $z^r$ from a coprime solution of $x^p+y^q=z^r$ with $x,y,z>1$ and $\frac1p+\frac1q+\frac1r<1$)
Comments
(1)
The summands are ordered by size, so $x^p<y^q$. Thus the solution with $z^r=512$ is written here as $13^2+7^3=2^9$, although some sources list the two summands in the other order.
(2)
The exponents $p$, $q$ and $r$ of each solution are shown in its label.
(3)
For any fixed positive exponents $p$, $q$ and $r$ with $\frac1p+\frac1q+\frac1r<1$, there are only finitely many coprime solutions [2].
(4)
The infinite family $1^p+2^3=3^2$ with $p>6$ has $x=1$ and gives the OEIS A214618 term $9$ [4]. It is represented by this comment rather than by rows, because $p$ is unbounded while the perfect-power triple is always $(1,8,9)$.
References
[1]
Adam S. Sikora, Fermat-Catalan and Tijdeman-Zagier Conjectures for Products, 2024. (arXiv)
[2]
Henri Darmon and Andrew Granville, On the equations $z^m=F(x,y)$ and $Ax^p+By^q=Cz^r$, Bulletin of the London Mathematical Society 27 (1995), 513-543. (doi) (MR)
Links
Similar tables
Good examples of Hall's conjecture —   records another family where two perfect powers nearly coincide
$abc$-triples of high quality —   stores high-quality $abc$-triples, and the $abc$ conjecture would imply the Fermat-Catalan conjecture
$abc$-triples of high merit —   stores the refinement of $abc$ quality by merit in the same circle of conjectures
Number of $p$-smooth $abc$-triples —   counts a finite search space for another form of the $abc$ equation
Data properties
Entries are of type: integer
Table is complete: no (it holds the nine solutions with $x,y,z>1$ among the ten known coprime solutions listed in [1]; Sikora's 2024 search found no other coprime solution with $\min(p,q,r)\leq113$ and $x^p,y^q,z^r<M_{\min(p,q,r)}$, where $M_2=2^{71}$, $M_3=2^{80}$, $M_4=2^{100}$ and $M_d=2^{113}$ for $5\leq d\leq113$)
Sources of data: [1], [4], [3], [5]
How they were obtained:

Every stored value is an exact integer. The generator checks each identity, each coprimality condition and each exponent inequality with integer arithmetic. It also checks the stored sums against the OEIS A214618 b-file after removing its first term $9$, which comes from the excluded family $1^p+2^3=3^2$.